Question

in the motion will control acceleration the velocity is reduct to zero in 5 second and after covering a distance of 100 metre the distance covered by the particle in next 5 sec will be​

Answer 1

Answer:

Explanation:

A = (v - u)/t ,

= (0 - u)/t ,

= -u / (5 s) ,

S = ut + 0.5at² ,

100 = 5u + (0.5 × [-u / (5 s)] × (5 s)²) ,

100 = 5u - 2.5u ,

100 = 2.5u ,

u = 40 m/s ,

If u = 40 m/s then ,

a = -u / (5 s) ,

= -(40 m/s) / (5 s) ,

= -8 m/s² ,

Displacement covered in 10 seconds ,

S = ut + 0.5at² ,

= (40 m/s × 10 s) + [0.5 × (-8 m/s² × (10 s)²] ,

= 0 m ,

Particle travelled 100 m in first 5 seconds and in next 5 seconds it travels 100 m back to initial position. Hence we got Displacement after 10 seconds equal to zero.

Hope it helps.

Answer 2

Answer:

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