in the network calculate the equivalent resisrance between the point A and point B
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2 ohm
Look at the points A and C . Between them , there are 2 resistors , say R1 and R2 of 2ohm each . We can see that both of them are in series .
So, their equivalent resistance =R1+R2 = 2+2=4 ohm .
Similarly , between C and A , again there are 2 resistors of 2 ohm each . So, their equivalent resistance = 2+2=4 ohm .
Now these two equipment resistances are in parallel with each other So, equivalent resistance = 1/4+1/4 =2/4 =4/2 = 2 ohm .
So ur answer is 2 ohm
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answer is 2 of these question
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