In the network shown in the fig. Points A, B and Care at potentials
of 70 V, O V, and 10 V, respectively.
(A) Point D is at a potential of 40 V
(B) The current in the sections AD, DB, DC are in the ratio 3:2:1
(C) The current in the sections AD, DB, DC are in the ratio 1:2:3
(D) The network draws a total power of 200 W.
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A is the correct option.
we have to use that the incoming current is equal to the outgoing current...
refer to the attached photos for the answer!!!
HOPE THIS WAS HELPFUL. :-D
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