Question

in the network shown the resistance between two adjacent junction is r. equivalent resistance between points A and B is​

Answer 1

Answer:

Here the equivalent resistance of each triangle is Req1=(R+R)+R(R+R)R=(2/3)R

Now reduce the side by connecting resistance in series as shown in figure.

Here, Req2=(2/3)R+(2/3)R=(4/3)R

Now the circuit is a balanced Wheatstone bridge. So middle resistor R is not working.

Thus, RAB=[(4/3)R+R]+[(4/3)R+R][(4/3)R+R][(4/3)R+R]=67R  

Explanation:

plz mark me as brainlist