Question

In the number 346N7, find the smallest whole number N to make the resulting number is divisible by 3​

Answer 1

3+4+6+7+N = 20+N

put N = 1

21 / 3 = 7

so RIGHT ANSWER is 1

PLEASE MARK AS BRAINLIEST

Answer 2

In context to question asked,

We have to determine the value of N for which the given number 346N7 is divisible by 3.

As we know that,

Any numbers are divisible by 3, only if the sum of the digits of the particular number is divisible by 3.

So, the given number 346N7 will be divisible by 3,

If and only If the sum of digits i.e. value of $3+4+6+N+7$ will be divisible by 3.

So, after solving we will get the value of N as,

$3+4+6+N+7= 20+N\\=>If\: N = 1=>Sum = 20+1=21\:(Divisible\:by\:3)\\=>If\: N = 4=>Sum = 20+4=24\:(Divisible\:by\:3)\\=>If\: N = 7=>Sum = 20+7=27\:(Divisible\:by\:3)$

So, the value of N will be 1,4 or 7. i.e. if we put any values from (1, 4 ,7) in place of N in the given number, the number obtained will be completely divisible by 3.