Question

in the number 53.436, how many times is the place value of the digit 3 to the right of the digit 4 to that of the digit 3 to the left of the digit 4?

Answer 1

Given:  53.436

To Find:   how many times is the place value of the digit 3 to the right of the digit 4 to that of the digit 3 to the left of the digit 4

Solution:

53.436

5* 10¹  + 3 * 10⁰  + 4 * 10⁻¹  + 3 * 10⁻²  + 6 * 10⁻³

= 50  + 3  +  4/10  + 3/100   + 6/1000

Place value of digit 3 to the left of the digit 4 = 3

Place value of digit 3 to the right  of the digit 4 = 3/100

Let say N times is the place value of the digit 3 to the right of the digit 4 to that of the digit 3 to the left of the digit 4

=>  3/100  = N * 3

=> N = 1/100

=> N = 0.01

0.01 times or 1/100 times is  the place value of the digit 3 to the right of the digit 4 to that of the digit 3 to the left of the digit 4

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