Question

in the number 53.436 how many times is the place value of the digit 3 to the right of the digit 4 to that of the digit 3 to the left of the digit 4​

Answer 1

Step-by-step explanation:

Given: 53.436

To Find: how many times is the place

value of the digit 3 to the right of the digit 4 to that of the digit 3 to the left of the digit 4

Solution:

53.436

5* 10' + 3 * 10° + 4 * 10-1 + 3 * 10-2 + 6 * 10-3 = 50 + 3 + 4/10 + 3/100 + 6/1000

Place value of digit 3 to the left of the

digit 4 = 3 Place value of digit 3 to the right of the digit 4 = 3/100

Let say N times is the place value of the digit 3 to the right of the digit 4 to that of the digit 3 to the left of the digit 4

=> 3/100 = N*3

=> N = 1/100

=> N = 0.01

0.01 times or 1/100 times is the place value of the digit 3 to the right of the digit 4 to that of the digit 3 to the left of the digit 4