Question

In the old days how were the following estimated:
(a) A day _____________
(b) A month ___________
(c) A year _____________​

Answer 1

Answer:

x

2

×x

6

=x

2+6

=x

8

{x}^{5} \div {x}^{3} = {x}^{5 - 3} = {x}^{2}x

5

÷x

3

=x

5−3

=x

2

{( {x}^{2} })^{4} = {x}^{8}(x

2

)

4

=x

8

Answer 2

Answer:

b option is correct dear