Question

In the organic compound $CH_{2} = CH-CH_{2}-CH_{2}-C \equiv CH, the \ C_{2}-C_{3}$ bond is the pair of hybridised orbitals involved in the formation of:
(a) sp-$sp_{2}$
(b) sp-$sp_{3}$
(c) $sp_{2}$-$sp_{3}$
(d) $sp_{3}$-$sp_{3}$

Answer 1

Given, the organic compound,

$CH_{2}=CH-CH_{2}-CH_{2}-C$≡CH

We have numbered the organic compound from the last.  

6          5         4           3        2      1

$CH_{2}=CH-CH_{2}-CH_{2}-C$≡CH

From this, we have the carbon atoms sp, sp, $sp^3$, $sp^3$, $sp^2$, and $sp^2$ hybridized orbitals in 1, 2, 3, 4, 5, and 6 places respectively.

Hence, in the formation of $C_{2}-C_{3}$ bond the pair of hybridized orbitals involved is $sp-sp^3$.