In the pair of equations x-3y-7=0 and 3x-3y-15=0, the value of x is *
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Answer:
x-3y=7 (1)
3(x-y-5)=0
x-y-5=0/3
x-y=5 (2)
subtracting 1 and 2
x-3y-x+y=7-5
-2y=2
-y=2/2
y=-1
x-y=5
x-(-1)=5
x+1 =5
x=4
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