Question

In the parabola y2 = 4ax, the length of the chord passing through the
vertex and inclined to the axis at an angle 450 is ---------
a)√2a b)2a√2 c)2a d )4a√2

Answer 1

Answer:

Let the length of chord be L then the coordinate of point where chord cut the parabola is

x1​=Lcosθy1​=Lsinθ

We have the parabola equation as follow

y2=4ax

This point will satisfy the equation of parabola

⇒(Lsinθ)2=4a(Lcosθ)⇒L=sin2θ4acosθ​

Step-by-step explanation: