in the parallelogram ABCD, angle A =(3×-12)°,angleB=(2x-32)°,find the value of x & fune the measure ofcangle c and angle d.
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Given Two angles of a parallelogram are (3x + 12) and (2x - 32).
We know that the sum of adjacent angles of a parallelogram is 180.
=> (3x+12) + (2x - 32) = 180
=> 3x + 12 + 2x - 32 = 180
=> 5x-20180
=> 5x = 180 + 20
=> 5x = 200
=> x = 40.
Now,
The measure of angle A = 3x + 12
= 3(40) + 12
= 120 + 12
= 132.
The measure of angle B = 2x - 32
= 2(40) - 32
= 80-32
= 48.
We know that the opposite angles of a parallelogram are equal.
Hence, the measure of angle C = 132. Hence, the measure of angle D = 48.
Therefore, the angles are A = 132, B =
48, C = 132, D = 48.
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