Question

in the parallelogram ABCD angle A is equal Angle B + 50 then find the measure of each angle of the quadrilateral ABCD​

Answer 1

Answer:

Angle A = 115 degrees

Angle B = 65 degrees

Angle C = 115 degrees

Angle D = 65 degrees

Step-by-step explanation:

In parallelogram, sum of adjacent angles is equal.

Therefore, A+B=180

Or B+50+B=180

Or B=65 degrees

Angle A= B+50 = 115 degrees

In parallelogram, opposite angles are equal.

Angle A= Angle C= 115 degrees

Angle B= Angle D=65 degrees

Answer 2

$\angle A = \angle C = 115$°

$\angle B = \angle D = 65$°

Step-by-step explanation:

In a parallelogram ABCD

$\angle A = B+50$

since , in a parallelogram sum of the  adjacent angles  are 180°

let $\angle B = B$

then ,

$\angle A +\angle B = 180$

putting the values

B+50+B= 180°

2B+50= 180°

2B= 180°-50°

2B= 130°

B = 65°

so, $\angle B = 65$°

$\angle A = B +50 = 65+50 = 115$°

now, opposites angles of the parallelogram are equal

∴ $\angle A = \angle C$ = 115°

and $\angle B = \angle D = 65$°

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