Question

in the parallelogram.ABCD AS SHOWN IN THE FIG.16.20 FIND ANGLES A,B,Cand D.​

Answer 1

Answer:

Let ABCD be a parallelogram in which ∠A=65

∘

.

Since AD∥BC we can treat AB as a transversal. So,

∠A+∠B=180

∘

65

∘

+∠B=180

∘

∠B=180

∘

−65

∘

∠B=115

∘

Since the opposite angles of a parallelogram are equal, we have

∠C=∠A=65

∘

and ∠D=∠B=115

∘

Hence, ∠B=115

∘

,∠C=65

∘

and ∠D=115

∘