Question

In the parallelogram ABCD
CA=65, find other angles of a square abcd

​

Answer 1

Answer:

Let ABCD be a parallelogram in which ∠A=65

∘

.

Since AD∥BC we can treat AB as a transversal. So,

∠A+∠B=180

∘

65

+∠B=180

∘

∠B=180

∘

−65

∘

∠B=115

∘

Since the opposite angles of a parallelogram are equal, we have

∠C=∠A=65

∘

and ∠D=∠B=115

∘

Hence, ∠B=115

∘

,∠C=65

∘

and ∠D=115

∘Please mark me brainlist

Answer 2

Answer:

answer mill gya hain na gg gg