Question

in the parallelogram ABCD measure of A is three times the measure of B.find the four angles
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Answer 1

Angle A is 3 times of angle B

we don't know the angle B ,hence we let it as

angle B = x

So Angle A is 3times of B .

Angle A=3x

Angle C=3x .......( opposite side of parallogram are equal)

So Angle D also equal to Angle B

Angle B= Angle D

x= x

So

$\color{red}{sum \: of \: all \: angle \: is \: 360}$

Hence,

x+3x+3x+x=360°

8x=360°

x=360°/8

x=45°

Hence

Angle B=Angle D = 45°

Angle A°=Angle C = 3*x

3*45

135°

Hence

Angle A= 135°

Angle B =45°

Angle C = 135°

Angle D = 45°

Hope it's help you ☺️❤️☺️❤️

Answer 2

Step-by-step explanation:

a+b+c+d=360

a(length )=3times breadth (3b)b

3b+3b+b+b=360

8b=360

b=360/8

b=45

therefore,

b(breadth )=45

A(length)=3b=3×45=135

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