Math, asked by ms1763334, 1 month ago

In the parallelogram ABCD,P is the mid point of the diagonal BD. If PB bisects /_ ABC , then the measure of /_ APB is​

Answers

Answered by uratnakar1980
0

Answer:

ABCD is ∥gm

AB∥CD

AE∥FC

⇒AB=CD

    21AB=21CD

    AE=EC

AECF is ∥gm

In △DQC

F is mid point of DC 

FP∥CQ

By converse of mid point theorem P is mid point of DQ

⇒DP=PQ     (1)

∴AF and EC bisect BD

In △APB

E is mid point of AB

EQ∥AP

By converse of MPT ( mid point theorem )

Q is mid point of PB

⇒PQ=QB   (2)

By (1) and (2)

⇒PQ=QB=DP

AF and EC bisect BD..

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