Question

in the parallelogram ABCD the area of ∆ ABC is 10 sq. cm then the area of ABCD = ____________ sq. cm.

Answer 1

Step-by-step explanation:

$\huge\mathbb\blue{♡Answer♡}$

Each of the diagonals of a parallelogram divides it into two congruent triangles.

$area~of~parallelogram= \\ area~ of~triangle ABC~+triangle ACD \\ area ~of ~triangle~ABC=10cm²\\ its ~a ~parallelogram ~so ~ACD=10cm² \\ parallelogram~area = 20cm²$

$\large\red{\boxed{\mathcal{Thank\:my\:answer\:if\:its\:helps}}}$

Answer 2

Answer:

20

ABC + ACD

ACD =10

ABC=10

10+10=20