Question

In the parking lot shown, the lines that mark the width of each space are parallel. If ∠1 = (2x–3y)°, ∠2 = (x +39)°, find x and y.

Answer 1

Answer:

x = 60  & y = 20

x = 81  & y = 34

Step-by-step explanation:

Parking lot picture attached as per fig.

∠1 = (2x–3y)°, ∠2 = (x +3y)°

now ∠2 + 60° = 180°

=> ∠2 = 120°

=> (x +3y)° = 120°

=> x + 3y = 120     Eq1

∠1 = 60°

=> (2x–3y)° = 60°

=> 2x - 3y = 60    Eq2

Adding eq 1 & Eq 2

=> 3x = 180

=> x = 60

60 + 3y = 120

=> 3y = 60

=> y = 20

x = 60  & y = 20

if we take data as per question : then

∠1 = (2x–3y)°, ∠2 = (x +39)°

x +39 = 120

=> x = 81

2x - 3y = 60

=> 2 * 81 - 3y = 60

=> 3y = 102

=> y  = 34

x = 81  & y = 34