Question

) In the picture below, the top vertex of a triangle is joined to themidpoint of the opposite side and then the point dividing this line in theratio 2:1 is joined to the other two vertices:Prove that the areas of all three triangles in the picture on the right areequal to a third of the area of the whole triangle.​

Answer 1

Answer:

let area of ∆ ABC = x

'D' is the midpoint of BC

BD = CD

So, Area of ∆ ABD = Area of ∆ ADC

i.e x/2

'O' divides AD in the ratio 2:1

ratio of areas of ∆AOB, ∆ BOD = 2:1

Sum of ratio = 2+1= 3

Are of ∆ AOB = x/2× 2/3 = x/3

Area of ∆ BOD = x/2× 1/3 = x/6

so, area of ∆ BOC = x/6+x/6 = 2x/6 = x/3

i.e all three triangles have same area

x/3 indicates that areas of all three triangles are equal to a third of area of whole triangle...

Are u studying in 9th

I am also studying in 9th

hope it helps you

Answer 2

Answer:

I am also in class 9th .

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