In the picture, triangle XYZ is similar to triangle MPN. The measures of each of the sides in both triangles are given.
What is the ratio, in simplest form, between the length of a side in ∆XYZ and the length of its corresponding side in ∆MPN?
Answer is 3/2
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∆XYZ ~ ∆LMN [Given] ∴ ∠X ≅ ∠L ∠Y ≅ ∠M > ∠Z ≅ ∠N [Corresponding angles of similar triangles] XY/LM = YZ/MN = XZ/LN [Corresponding sides of similar triangles]
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c. 3/2
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