Question

in the poly P(x) x^2-10x+2 what should be the value of x to get the least possible value at p(x)

Answer 1

Answer:

0 or 10

Step-by-step explanation:

x²-10x+2

let's take p(x)=0

=0²-10(0)+2

=0-0+2

=2

now let's take p(x)=10

=10²-10(10)+2

=100-100+2

=0+2

=2

therefore 0 or 10 can be the least possible