In the polynomial p(x)=x²+ax+b, p(1)=4, p(2)=9. Find a and b. Also find p(3)
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Explanation:
p(x) = x²+ax+ b
p(1)=4
p(1)= 1²+a+b=4
a+b=3
b=3-a------1
p(2)=9
p(2)=2²+2a+b=9
2a+b=5
2a+3-a=5
a=2--------2
substitute 2 in 1
b= 3-2=1
p(3)= 3²+3a+b
=9+3(2)+1
= 9+6+1
=16
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