Question

in the ∆ PQR , Find the value of x​

Answer 1

Answer:

this is not the full question plz write the question again

Answer 2

Answer:

Note: Firstly you have to label the triangle...like it is given in the question that they are talking about ∆ PQR. So, label it such as one angle is coming out to be P, another Q and the last - R.

Now, In ∆ PQR

Lets assume 2x+45°=P

Also, Q = 5x°

and let R = x

Now, as we all know that the sum of three angles of a triangle is equal to 180°, we will use it here...

Let's see how:-

Angle P + Angle Q + Angle R = 180°

(2x+45°) + (5x°) + x = 180° (putting the values we just assumed above.)

8x + 45° = 180°

8x = 180° - 45°

8x = 135°

x = 135/8

Thus, x = 16.8 or 17.0 (17) approx.

Therefore,

Angle R = 16.8° (x)

Angle Q = 78.6 (2x+45°)

Angle P = 84° (5x°)

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