In the ΔPQR, S and T are points on sides PQ and PR respectively such that ST∥QR. If PT = 1 cm; PS=1.5 cm and SQ=3 cm, then find RT
Answers
Answered by
9
Step-by-step explanation:
It's given that PS = 6, SQ = 9, PR = 12.5.
ST & QR are parallel.
Then basic by proportionality theorem
QS / SP = TR / PT.
Adding 1 both sides
=> (QS + SP) / SP = (TR + PT) / PT
=> (9 + 6) / 6 = 12.5 / PT
Here TR + PT = PR = 12.5
=> 15/6 = 12.5 / PT
=> PT = 5.
TR = 12.5 - PT = 7.5
I hope, it's clear now.
Answered by
5
Step-by-step explanation:
ANSWER
ST is parallel to QR (since ST is mid-point of PQ and PR) by proportionality theorem
PQ
PS
=
QR
ST
⇒
PS+PS
PS
=
QR
ST
⇒
2
1
=
QR
ST
⇒QR=2×ST
⇒2×6.2
⇒12.4
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