Question

In the preceding question if the bob is released from the horizontal position, what will be it's velocity at the lowest position?​

Answer 1

Answer:

v =√20 m/s

Explanation:

Bob is released from the horizontal position. The potential energy of Bob at this position will be

P.E = mgl

At vertical position, the total energy will be equal to Kinetic energy (total P.E will be converted to K.E). K.E = mv^2/2

Energy conservation:

mgl = mv^2/2

v^2 = 2gl

v^2 = 20

v = √20 m/s

Other method:

v = -Aωsinωt

put A = √2l, ω = 2π/T, t = T/4

v = - √2lωsin(π/2)

v = - √2lω

ω = √g/l

v = - √2gl

v = - √20 m/s

|v| = √20 m/s

Answer 2

Answer:

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Explanation:

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