In the presence of excess of anhydrous SrCl2, The amount of water taken up is governed by Kp = 1012 atm for the following
reaction at 273 K
SrCl2.2H20 + 4H20 = SrCl6H2O
(9)
HO
What is equilibrium vapour pressure (in torr) of water in a closed vessel that contains SrCl2.2H20?
Answers
Given info : In the presence of excess of anhydrous SrCl₂, The amount of water taken up is governed by Kp = 10¹² atm for the following reaction at 273 K,
SrCl₂.2H₂O (s) + 4H₂O (g) ⇒ SrCl₂.6HO (s)
To find : the equilibrium vapor pressure in torr of water in a closed vessel that contains SrCl₂.2H₂O.
solution : At equilibrium,
Kp = 1/(PH₂O)⁴
⇒10¹² = 1/(PH₂O)⁴
⇒(PH₂O) = 10¯³ atm
We know, 1 atm = 760 torr
Therefore, pressure of water in the vessel is 10¯³ × 760 torr = 0.76 torr.
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