Question

In the primary coil of a transformer ir a current of 2 ampere is reduced to znowie 3 milliseconds, an induced emt of 200 volts is produced in its secondary coll. Calculate the coefficient of mutual inductance of the transformer​

Answer 1

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The emf induced in secondary is given by

e= −MdI / dt⇒1000=M( 2-0/0.01 )

(since current is reduced dI = -ve)

⇒M= 1000×0.01 /2

=5.00H

Answer 2

Answer:

The emf induced in secondary is given by

e= −MdI / dt⇒1000=M( 2-0/0.01 )

(since current is reduced dI = -ve)

⇒M= 1000×0.01 /2

=5.00H

Explanation:

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