In the process of electrolysis of water, what is the ratio of the volume of gases collected at cathode and anode? (a) 1:1 (b) 2:1 (c) 3:2 (d) 3:1
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In electrolysis of water:
(a) Name the gas collected at cathode and anode.
(b) Why is volume of one gas collected at one electrode is double of anode?
(c) Why are few drops of dilute H
2
SO
4
added to water?
a) At cathode, H
2
is evolved and at anode O
2
is evolved.
b) At cathode, H
+
ion takes two electron to convert itself into H
2
gas. 2 moles of H
+
gives 1 mole of H
2
.
2H
+
(aq)+2e
−
→H
2
(g)
At anode, OH
−
ion releases two electrons to convert into water and O
2
. 2 mole OH
−
gives 0.5 mole O
2
, i.e why volume of one gas collected at one electron is double of another.
c) Acid is added to make the water conduct electricity as the distilled water is a non-conductor of electricity.
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