Question

. In the product of (4a3 + 5a2 – 11a) and (-15 + 3a – 7a2), the co-efficient of a4 is …………………… .

Answer 1

Answer:

The co-efficient of $a^4$ is -23

Step-by-step explanation:

$(4a^3 + 5a^2 - 11a)(-15 + 3a - 7a^2)$

$=4a^3(-15 + 3a - 7a^2) + 5a^2(-15 + 3a - 7a^2) - 11a(-15 + 3a - 7a^2)$

$=-60a^3 + 12a^4 - 28a^5 - 75a^2 + 15a^3 -35a^4 + 165a - 33a^2 + 77a^3$

$= - 28a^5 + 12a^4 -35a^4 + 77a^3 + 15a^3 - 60a^3 - 75a^2 - 33a^2 + 165a$

$= - 28a^5 - 23a^4 + 32a^3 - 108a^2 + 165a$

∴ The co-efficient of $a^4$ is -23

Answer 2

Answer:

-23 is the answer

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