Question

In the production of naoh why naoh near the cathode

Answer 1

Chlorine gas is also produced in this process. Solid sodium hydroxide is obtained from this solution by the evaporation of water. Principle — In castner-kellner method NaOH is prepared by the electrolysis of aqueous solution of NaCl (Brine). ... Chlorine produced at the anode is removed from the top of the cell.

During electrolysis of brine(aq. NaCl), NaCl and water are present as electrolyte.

Na+ (from NaCl) and H+(from water) tends to move to negative terminal (i.e cathode) while Cl- (from NaCl) and OH-(from water) tends to move to positive terminal(i.e anode).

Now only one from Na+ and H+ at cathode will get reduce which has higher standard reduction potential.

Standard reduction potential of Na+ (E°=-2.71V) which is quite less from that of H+ ion (E°=0.00V), H+ reduces at cathode and H2 gas will produce. Similarly only one from Cl-and OH- will get oxidise at anode, which has lower standard reduction potential. Standard reduction potential of Cl-is. E°=1.36V while that of H2O/OH- is 1.23 V. So Standard reduction potential of hydroxide ion is less than that of Cl- ion , which implies that O2 must be released by oxidation of hydroxide ion.

Answer 2

Answer:

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Explanation:

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