Question

In the property of indices
${a}^{m} \div {a}^{n} = {a}^{m - n}$
Taking m = n, show that
${a}^{0} = 1$

​

Answer 1

Given,

a^m ÷ a^n = a^(m - n)

if m = n

then,

a^m ÷ a^m = a^(m - m)

a^m/a^m = a⁰

On cancelling

1 = a⁰

therefore, a⁰ = 1

hence proved!!