In the pulley system shown the movable
pulleys A, B and C have mass m each, D and
E are fixed pulleys. The strings are vertical,
light and inextensible. Then,
u
D
E
B
Answers
Answer:
Since, all strings are connected to each other, it will have some tension at all point, let it be T.
Considering the acceleration of pulley, A,B and C is a
1
,a
2
and a
3
downward.
→ according to constrain equation,
∑T.a=0
−2Ta
3
−T.a
2
−Ta
1
=0
2a
3
+a
2
+a
1
=0→(1)
Applying Newton''s laws on each block,
10−2T=a
3
→(2)
10−T=a
2
→(3)
10−T=a
1
→(4)
From equation (2) and (3)
−T=a
3
−a
2
T=a
2
−a
3
→(5)
putting it in
10−a
2
+a
3
=a
2
2a
2
=10+a
3
→(6)
Solving (2) and (4), we get,
a
1
=a
2
=
3
10
,a
3
=−
3
10
T=
3
20
Newton
Explanation:
I I hope this is your answer please follow me and mark me brainly
Since, all strings are connected to each other, it will have some tension at all point, let it be T.
Considering the acceleration of pulley, A,B and C is a
1
,a
2
and a
3
downward.
→ according to constrain equation,
∑T.a=0
−2Ta
3
−T.a
2
−Ta
1
=0
2a
3
+a
2
+a
1
=0→(1)
Applying Newton''s laws on each block,
10−2T=a
3
→(2)
10−T=a
2
→(3)
10−T=a
1
→(4)
From equation (2) and (3)
−T=a
3
−a
2
T=a
2
−a
3
→(5)
putting it in
10−a
2
+a
3
=a
2
2a
2
=10+a
3
→(6)
Solving (2) and (4), we get,
a
1
=a
2
=
3
10
,a
3
=−
3
10
T=
3
20
Newton
Explanation:
I I hope this is your answer please follow me and mark me brainly