In the quadratic equation kx^2-6x-1=0 determine the value of k for which the equation does not have any real roots
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Step-by-step explanation:
Given equation :- kx² - 6x - 1 = 0
The equation does not have any real roots then ,
b² - 4ac < 0
( -6 )² - 4k × ( -1 ) < 0
36 + 4k < 0
4k < -36
k < - 9
∴ When k < -9 , then the equation does not have any real roots.
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