Math, asked by aggarwaltanya3002, 1 year ago

In the quadratic equation kx^2-6x-1=0 determine the value of k for which the equation does not have any real roots

Answers

Answered by Ashishkumar098
29

Answer:

Step-by-step explanation:

Given equation :- kx² - 6x - 1 = 0

The equation does not have any real roots then ,

b² - 4ac < 0

( -6 )² - 4k × ( -1 ) < 0

36 + 4k < 0

4k < -36

k < - 9

∴ When k < -9 , then the equation does not have any real roots.

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