Math, asked by vishu126191, 1 month ago

In the quadratic equation x2 + (p + iq) x + 3i = 0 , p & q are real. If the sum of the squares of the roots is 8 . find the value of p and q

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Answers

Answered by TheBrainlistUser
1

\large\underline\mathfrak\red{Given \:  :- }

  • p and q are real.
  • x² + (p-iq)x + 3i = 0 is 8.

\large\underline\mathfrak\red{To  \: find \:  :- }

  • p and q

\large\underline\mathfrak\red{Solution \:  :- }

We know that,

\sf{x {}^{2} + (p + iq)x + 3i = 0 } \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \\ \sf{(α+β) = -(q-iq),αβ=3i}

Squaring,

\sf{α²+β² = (α+β)² -2αβ = [-(p+iq)] -6i }</p><p>

Required

\sf\implies{(p {}^{2}  - q {}^{2}) + i(2pq - 6) = 8} \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \\ </p><p>\sf\implies{p {}^{2}  - q {}^{2} = 8 \: and \: pq = 3 }  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \\ </p><p>\sf\implies{p = 3,q = 1 \:  \: or \:  \: p =  - 3,q =  - 1}

Values :-

p = 3 , q = 1 or p = -3 , q = -1

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