Question

In the quadratic polynomial t2 - 16, sum of the zeroes is
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Answer 1

The sum of the zeros is 0!

(-4,4)

Refer to the attached img for the detailed solution :)

Answer 2

Answer:

t²- 16 = 0

⇒ (t)² - (4)² = 0

⇒(t-4) × (t+4) = 0                                            [ using identity - a²- b² = (a+b)(a-b) ]

∴ t = 4 and t = -4

hence the zeroes are 4 and -4

so, sum of zeroes = 4 + (-4) = 4 - 4 = 0

ANSWER = 0