In the quadrilateral ABCD, BE=EC, m angle ADE=50⁰, m angle DAB=130⁰ and m andle ABE=60⁰. Find m angle EBC
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give the quadrilateral
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Step-by-step explanation:
Sol.
In quadrilateral ABCD
angle BAD=130*}
angle ADE=50* } (given)
angle ABE=60* }
angle BED= BAD + ADE + ABE + BED= 360*
let angle BED be ‘x’
130+50+60+x=360*
x=120*
so angle BED is also 120*
angle BEC is 180-120 (linear pair)
angle BEC=60
in /\ BEC side BE=BC so it is a iso. triangle
In iso. triangle base angles are equal.
so angle BEC=BCE
so BCE is 60*
BCE+BEC+CBE=180 (angle sum prop. of triangle)
let CBE be ‘y’
60+60+y=180
y=60*
so angle CBE= 60*
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