Question

in the quadrilateral ABCD, CO and DO are the bisects of LC and LD respectively prove that:- LCOD=1/2 (LA+LB) ?​

Answer 1

Answer:

In △COD,

∠COD + ∠1 + ∠2 = 180°

∠COD = 180° − (∠1 + ∠2)

∠COD=180°- ½(∠C+∠D)

∠COD=180°-½ [360 −(∠A+∠B)]

∠COD= ½ (∠A+∠B)

Answer 2

In △COD,

∠COD+∠1+∠2=180*

∠COD=180 −(∠1+∠2)

∠COD=180 − 1/2 (∠C+∠D)

∠COD=180 -1/2 [360 −(∠A+∠B)]

∠COD= 1/2 (∠A+∠B)