Question

In the quadrilateral ABCD, DA perpendicular to AB and CB perpendicular to AB. Prove that <C + <D = 180°.

Answer 1

Answer:

you can do it by *Angle Sum property of a Quadrilateral* !

Step-by-step explanation:

Given :<A = 90 °

<B = 90°

To prove :< C + < D = 90°

Proof : W.K.T All sums of a Quadrilateral sum up to 360

°-->( < A + < B ) + < C + < D = 360°

(90+90) +<C + <D = 360°

180+ < C + < D = 360°

< C + < D = (360-180)°

< C + < D = 180°

Hence Proved !

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Answer 2

Answer:

angle A = 90° = angle B. (given)

=> angle A + angle B + angle C + angle D =360°

=> 90° + 90° + angle C + angle D = 360°

=> 180° + angle C + angle D = 360°

=> angle C + angle D = 360° - 180°

=> angle C + angle D = 180°

(HENCE PROVED)

Step-by-step explanation:

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