Question

In the quantitative determination of nitrogen, N2 gas liberated from 0.42 gm of a sample of organic compound was collected over water. If the volume of N2 gas collected was
100/11 ml at total pressure
860 mm Hg at 250 K,%by mass of nitrogen in the organic compound is
[Aq. tension at 250 K is 24 mm Hg and R = 0.08 L atm mol^-1K^-1?]
(A)10/3%
(B) 5/3%
(C)20/3%
(D)100/3%​

Answer 1

Answer:

Mark as Brainliest please

Explanation:

Here u go

cant type so many fractions sry

10/3 is the answer

Answer 2

Attachment.a) 2nd part b) 2 method

Given :-

• N2 gas liberated from 0.42 gm

• Volume of N2 gas collected was100/11 ml at total pressure 860 mm Hg at 250 K

To Find :-

%by mass of nitrogen in the organic compound .

Solution :-

The volume of dry nitrogen at STP is Vo =

▶ $\dfrac{P1V1}{T1}$ × $\dfrac{To}{Po}$

$= \dfrac{(860 - 24) \times \dfrac{10}{11} }{250} \times \dfrac{273}{760}$

➡ 10.92 ml

Percentage by mass of nitrogen =

▶ $\dfrac{28 \timesVo\times 100} {22400 \times \: m}$

▶$\dfrac{28 \times10.92\times 100}{22400 \times \:0.42 }$

▶$\dfrac{10}{3}$ %

▶ The % by mass of nitrogen in the organic compound is Option.a $\dfrac{10}{3}$ %.

➡Option A. 10/3 %

Second part not clear due to latex error,

So it refers to the attachment .

________________________________

If first method is not clear

I provided a second method in # attachment. ✔

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