Physics, asked by shrutirajput1827, 5 hours ago

In the question 130 the vertical component of the velocity is​

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Answered by radhikanagod1959
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The vertical component of the velocity of projectile is:

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Initial velocity = V angle of projectile = a Vertical component of initial velocity = Vsintheta at maximum height Vf = 0 V^2 - mu^2 = 2as 0 - (Vsintheta)^2 = - 2gh h = (Vsintheta)^22g h^1 = h^1/2 h^1 = (Vsintheta)^24g time taken to reach half of maximum height. h^1 = mu t + 12at^2 V^2sin^2theta4g = Vsintheta t + 12 ( - 10 ) t^2 200t^2 - 40rsintheta t + V^2sin^2theta = 0 t = (√(2)±1) Vsintheta10√(2) Vertical component of velocity Vy = mu + at = Vsintheta - g × (√(2)-1) Vsintheta10√(2) Vy = Vsintheta√(2)

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In the question 130 the vertical component of the velocity is

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Answer:career planning is your answer hope it helps

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