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Angle CDE IS 35°AND ANGLE BDEVIS 55°
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In the given figure CD is perpendicular to AB
so, angle CDE= 90°
(i) angle CDE= x
x+2x-15 = 90
3x=90+15
x= 105/3
x= 35°......(1)
(ii) angle BDE = 2x-15°
=2(35)-15 from(1)
=70-15
= 55°
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