In the reactant of KMnO, with an oxalate in acidic medium. Mno, is reduced to Mn?* and C20.is
oxidised to CO2. Hence, 50 ml of 0.02 M KMnO, is equivalent to
1) 100 ml of 0.05 M H,C,04
2) 50 ml of 0.05 M HC,04
3) 25 ml of 0.2 MH.C,04
4) 50 ml of 0.10 M H2C2O4
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In the reactant of KMnO, with an oxalate in acidic medium. Mno, is reduced to Mn?* and C20.is
oxidised to CO2. Hence, 50 ml of 0.02 M KMnO, is equivalent to
1) 100 ml of 0.05 M H,C,04
2) 50 ml of 0.05 M HC,04
3) 25 ml of 0.2 MH.C,04
4) 50 ml of 0.10 M H2C2O4✔️✔️✔️
Answered by
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In the reactant of KMnO, with an oxalate in acidic medium. Mno, is reduced to Mn?* and C20.is
oxidised to CO2. Hence, 50 ml of 0.02 M KMnO, is equivalent to
1) 100 ml of 0.05 M H,C,04
2) 50 ml of 0.05 M HC,04
3) 25 ml of 0.2 MH.C,04
4) 50 ml of 0.10 M H2C2O4
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