Chemistry, asked by advithavydhikpbuysm, 10 months ago

In the reactant of KMnO, with an oxalate in acidic medium. Mno, is reduced to Mn?* and C20.is
oxidised to CO2. Hence, 50 ml of 0.02 M KMnO, is equivalent to
1) 100 ml of 0.05 M H,C,04
2) 50 ml of 0.05 M HC,04
3) 25 ml of 0.2 MH.C,04
4) 50 ml of 0.10 M H2C2O4

Answers

Answered by Anonymous
0

In the reactant of KMnO, with an oxalate in acidic medium. Mno, is reduced to Mn?* and C20.is

oxidised to CO2. Hence, 50 ml of 0.02 M KMnO, is equivalent to

1) 100 ml of 0.05 M H,C,04

2) 50 ml of 0.05 M HC,04

3) 25 ml of 0.2 MH.C,04

4) 50 ml of 0.10 M H2C2O4✔️✔️✔️

Answered by Anonymous
11

\large\underline\bold{ANSWER \red{\huge{\checkmark}}}

In the reactant of KMnO, with an oxalate in acidic medium. Mno, is reduced to Mn?* and C20.is

oxidised to CO2. Hence, 50 ml of 0.02 M KMnO, is equivalent to

1) 100 ml of 0.05 M H,C,04

2) 50 ml of 0.05 M HC,04

3) 25 ml of 0.2 MH.C,04

4) 50 ml of 0.10 M H2C2O4

\huge{\underline\bold{OPTION:- D \:\: \huge{\red{\checkmark}}}}

Similar questions