Question

in the reaction 2A+4B---->3C+4D when 6 moles of A react with 6 moles of B then (1)which is limiting reagent (2) calculate the amount of C formed​

Answer 1

Answer:

2A+4B⟶3C+4D

2A=5 moles

4B=6 moles

The limiting agent is B.

as 5 moles of A requres 10 moles of B but only 6 moles are present.

Hence, 2 moles of A=4 mole of B.

x=6 moles of B.

x=

4

2×6

=3 moles.

Amount of C consumed =

2

3×3

=4.5 moles of C.