Question

In the reaction 2n2o5 gives 4no2 +o2 initial pressure is 500 atm and rate constant k is 3.38*10^-5 sec after 10 minutes the final pressure of n2o5 is

Answer 1

Answer:490 atm

Explanation:By using the equation for first order reaction,the final pressure can be calculated

Answer 2

The final pressure of $N_2O_5$ after 10 minutes is 490.2 atm

Explanation:

For the given chemical reaction:

$2N_2O_5\rightarrow 4NO_2+O_2$

Rate law expression for first order kinetics is given by the equation:

$k=\frac{2.303}{t}\log\frac{p^o_A}{p_A}$

where,

k = rate constant  = $3.38\times 10^{-5}s^{-1}$

t = time taken for decay process = 10 min = 600 s   (Conversion factor: 1 min = 60 seconds)

$p^o_A$ = initial pressure of the sample = 500 atm

$p_A$ = final pressure of the sample = ?

Putting values in above equation, we get:

$3.38\times 10^{-5}=\frac{2.303}{600}\log\frac{500}{p_A}\\\\p_A=490.2atm$

Learn more about first order kinetics:

https://brainly.in/question/4482242

https://brainly.com/question/12839246

#learnwithbrainly