Question

In the reaction 2P+Q=3R+S if 2 mol each of P and Q taken initially in a 1 L flask what will be the concentration of Q at equilibrium

Answer 1

Answer:

Explanation:

Option (1) [P] < [Q]

Explanation:

In the reaction 2 moles of P reacts with 1 mole of Q to give 3 moles of R and 1 mole of S

If [R] = 3x and [S] = x

Then [P]=2-2x and [Q]=2-x

Thus at equilibrium the concentration of Q will be more than that of P

Thus

[P] < [Q]

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