Question

In the reaction 4NH3+502 + 4NO + 6H,O, the rate of formation of NO is 1 x10'mole/litre - sec. The rate of disappearance of
O2 is
(A) 4 x 10-3
(B) 5 x 10-3
(C) 1.25 x 103
(D) 0.8 x 10-3​

Answer 1

Answer:

It seems like your question is a bit incorrect, especially the equation, but is we put NH3 and O2 as reactants and NO and H2O as products, and solve this, the answer would be option (c)1.25=10³

If this is the case and you want explanation, please let me know.