In the reaction 8Al + 3Fe304 +4A1203 + 9Fe, the
number of electrons transferred from reductant to
oxidant is :-
(1) 8 (2) 4 (3) 16 (4) 24
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Answer:
Explanation:
In this reaction,Al is oxidized by oxidant Fe from 0 to +3 oxidation state while Fe is reduced by reductant Al with oxidation state from +8/3 to 0.
Thus 24 electrons are transfered from reductant Al to oxidant Fe....
In case of Al ...on left side of equation it has 0 oxidation state and on right side has +3 as
2x+3(-2)=0
2x-6=0 => x=+6/2
x=+3
As there are 4 Al2O3,so 8 Al in it....thus
8×3=24
Its means Al loses 24 electrons and Fe also gains 24 electrons.
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