In the reaction, A+B⇔C+D, the equilibrium constant K is determined by taking 1 mole of A and 1 mole of B as initial amounts. If 2 moles of A and 3 moles of B are taken, then the equilibrium constant will be
A.) Unchanged
B.) 2 times
C.) 3 times
D.) 6 times
Answers
Answered by
2
Explanation:
The equilibrium reaction is A+B⇔C+D.
The initial concentrations of A,B,C and are 1 M,1 M,0 M and 0 M respectively.
At equilibrium, the concentrations of A,B,C and D are respectively (1−0.9=0.1M),(1−0.9=0.1M),0.9Mand0.9M respectively.
The expression for the equilibrium constant is K
c
=
[A][B]
[C][D]
.
Substitute values in the above expression.
K
c
=
0.1×0.1
0.9×0.9
=81.
Answered by
2
Explanation:
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