Chemistry, asked by ngiik, 3 months ago

In the reaction, A+B⇔C+D, the equilibrium constant K is determined by taking 1 mole of A and 1 mole of B as initial amounts. If 2 moles of A and 3 moles of B are taken, then the equilibrium constant will be

A.) Unchanged
B.) 2 times
C.) 3 times
D.) 6 times

Answers

Answered by itzsweety22
2

Explanation:

The equilibrium reaction is A+B⇔C+D.

The initial concentrations of A,B,C and are 1 M,1 M,0 M and 0 M respectively.

At equilibrium, the concentrations of A,B,C and D are respectively (1−0.9=0.1M),(1−0.9=0.1M),0.9Mand0.9M respectively.

The expression for the equilibrium constant is K

c

=

[A][B]

[C][D]

.

Substitute values in the above expression.

K

c

=

0.1×0.1

0.9×0.9

=81.

Answered by abhi230204
2

Explanation:

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.

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