Question

In the reaction below, 8.0 g of H2 react with 9.0 g of O2. Which of the following statements is true?
2 H2 + O2 -----> 2 H2O
a. The equation is not balanced.
b. The H2 is the limiting reactant.
c. The O2 is the limiting reactant.
d. 2.0 moles of H2O would be produced.
e. 36 grams of H2O would be produced

Answer 1

D is the correct option . 2.0 moles of H²O would be produced.

Answer 2

Answer:

The correct option is (c) The $O_{2}$ is the limiting reactant.

Explanation:

Two moles of hydrogen molecules react with one mole of oxygen to give two moles of water molecules.

In the question, we have 8g of hydrogen reacting with 9g of oxygen. We need to calculate the limiting reagent. This can be done by dividing the moles of elements by their coefficient.

First, convert the masses to moles by using the formula below.

$Moles= \frac{Mass}{Molar Mass}$

For $H_{2}$,

Mass- 8g

Molar Mass- 2g/mol

$Moles= \frac{8}{2} = 4mol$

For $O_{2}$,

Mass- 9g

Molar Mass- 32mol/g

$Moles=\frac{9}{32}= 0.28mol$

Now divide the moles of each element by their coefficient.

For $H_{2}$,

$\frac{4}{2}=2$

For $O_{2}$,

$\frac{0.28}{32}=0.009$

We see that $O_{2}$ is the limiting reactant.